F(t+1)=2t^2+5t-2

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Solution for F(t+1)=2t^2+5t-2 equation: 


Simplifying
F(t + 1) = 2t2 + 5t + -2

Reorder the terms:
F(1 + t) = 2t2 + 5t + -2
(1 * F + t * F) = 2t2 + 5t + -2
(1F + tF) = 2t2 + 5t + -2

Reorder the terms:
1F + tF = -2 + 5t + 2t2

Solving
1F + tF = -2 + 5t + 2t2

Solving for variable 'F'.

Move all terms containing F to the left, all other terms to the right.

Reorder the terms:
2 + 1F + -5t + tF + -2t2 = -2 + 5t + 2t2 + 2 + -5t + -2t2

Reorder the terms:
2 + 1F + -5t + tF + -2t2 = -2 + 2 + 5t + -5t + 2t2 + -2t2

Combine like terms: -2 + 2 = 0
2 + 1F + -5t + tF + -2t2 = 0 + 5t + -5t + 2t2 + -2t2
2 + 1F + -5t + tF + -2t2 = 5t + -5t + 2t2 + -2t2

Combine like terms: 5t + -5t = 0
2 + 1F + -5t + tF + -2t2 = 0 + 2t2 + -2t2
2 + 1F + -5t + tF + -2t2 = 2t2 + -2t2

Combine like terms: 2t2 + -2t2 = 0
2 + 1F + -5t + tF + -2t2 = 0

The solution to this equation could not be determined.

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